
Q:
What
is
the
frequency
representation
of
the
FM
sine
wave.
A:
*(/>
=
AT,J
n
m[b{f
-
f
c
-
n/J
+
6(f
+
f
c
+
n/J]
ß
=
1.692
J
0
(ß)
=
.4
Jj(ß)
=
.5
J
2
(ß)
=
.3
7
3
(ß)
=
.1
Q:
Measure
f
,
f
and
2Af.
What
is
the
frequency
deviation?
What
is
ß
and
the
bandwidth?
A:
f
=
(.75
xlO"
3
-
.615
xlO"
3
)"
1
=
7407
Hz
f
=
(1.36
xlO'
3
-
1265
xlO'
3
)"
1
=
10.526
-
lOKHz
2Af=3119
Hz
Af=1560Hz
ß
=
Af/f
m
=
1
.
5
6
Hz
B
=
2(1560)+
2000
=
5120
Hz
Lab
3
Solutions
Page
7
77
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